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\[\sqrt[2x]{(\frac{1}{{2}^{x}})}=\frac{\sqrt{2}}{2}\]
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((1/(2^x)))^(1/(2x))=sqrt(2)/2
((1/(2^x)))^(1/(2x))=sqrt(2)/2
\sqrt[2x]{(\frac{1}{{2}^{x}})}=\frac{\sqrt{2}}{2}
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