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\[\frac{6}{7}(3-5n)\ge \frac{3}{5}(1-9n)\]
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6/7(3-5n)>=3/5(1-9n)
6/7(3-5n) ≥ 3/5(1-9n)
\frac{6}{7(3-5n)}\ge \frac{3}{5(1-9n)}
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