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\[\log{\frac{75}{16}}-2\log{\frac{5}{9}}+\log{\frac{32}{243}}=\log{2}\]
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log(75/16)-2log(5/9)+log(32/243)=log(2)
log(75/16)-2log(5/9)+log(32/243)=log(2)
\log{\frac{75}{16}}-2\log{\frac{5}{9}}+\log{\frac{32}{243}}=\log{2}
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