Problem of the Week

Updated at Dec 31, 2018 4:43 PM

This week we have another equation problem:

How would you solve the equation \(\frac{4t-3}{5}+2=\frac{23}{5}\)?

Let's start!



\[\frac{4t-3}{5}+2=\frac{23}{5}\]

1
Subtract \(2\) from both sides.
\[\frac{4t-3}{5}=\frac{23}{5}-2\]

2
Simplify  \(\frac{23}{5}-2\)  to  \(\frac{13}{5}\).
\[\frac{4t-3}{5}=\frac{13}{5}\]

3
Multiply both sides by \(5\).
\[4t-3=\frac{13}{5}\times 5\]

4
Cancel \(5\).
\[4t-3=13\]

5
Add \(3\) to both sides.
\[4t=13+3\]

6
Simplify  \(13+3\)  to  \(16\).
\[4t=16\]

7
Divide both sides by \(4\).
\[t=\frac{16}{4}\]

8
Simplify  \(\frac{16}{4}\)  to  \(4\).
\[t=4\]

Done
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