Problem of the Week

Updated at Sep 25, 2023 1:54 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of \({t}^{2}+\sqrt{t}\)?

Check out the solution below!



\[\frac{d}{dt} {t}^{2}+\sqrt{t}\]

1
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[2t+\frac{1}{2\sqrt{t}}\]

Done