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\[\frac{1}{3}=\frac{\sqrt{x}-7}{\sqrt{x}+3}\]
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(1)/(3)=(sqrt(x)-7)/(sqrt(x)+3)
(1)/(3)=(sqrt(x)-7)/(sqrt(x)+3)
\frac{1}{3}=\frac{\sqrt{x}-7}{\sqrt{x}+3}
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