# Problem of the Week:Derivative of $${e}^{x}-x$$

Updated at Apr 17, 2017 2:13 PM

This week we have another calculus problem:

How do you differentiate $${e}^{x}-x$$?

Let's start!

$\frac{d}{dx} {e}^{x}-x$

 1 Apply the Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$$(\frac{d}{dx} {e}^{x})+(\frac{d}{dx} -x)$2 The derivative of $${e}^{x}$$ is $${e}^{x}$$${e}^{x}+(\frac{d}{dx} -x)$3 Apply the Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$${e}^{x}-1$Donee^x-1