Problem of the Week

Updated at Dec 10, 2018 5:38 PM

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Dec 10, 2018

This week we have another equation problem:

How would you solve \(4{x}^{2}+4(x+2)=16\)?

Let's start!

\[4{x}^{2}+4(x+2)=16\]

Expand

\[4{x}^{2}+4x+8=16\]

Move all terms to one side

\[4{x}^{2}+4x+8-16=0\]

Simplify \(4{x}^{2}+4x+8-16\) to \(4{x}^{2}+4x-8\)

\[4{x}^{2}+4x-8=0\]

Factor out the common term \(4\)

\[4({x}^{2}+x-2)=0\]

Factor \({x}^{2}+x-2\)

How?

\[4(x-1)(x+2)=0\]

Solve for \(x\)

How?

\[x=1,-2\]

Done