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Problem of the Week

Updated at Dec 2, 2019 2:53 PM

This week we have another equation problem:

How would you solve \(\frac{4(z-3)+2}{5}=2\)?

Let's start!



\[\frac{4(z-3)+2}{5}=2\]

1
Factor out the common term \(2\).
\[\frac{2(2(z-3)+1)}{5}=2\]

2
Multiply both sides by \(5\).
\[2(2(z-3)+1)=2\times 5\]

3
Simplify  \(2\times 5\)  to  \(10\).
\[2(2(z-3)+1)=10\]

4
Divide both sides by \(2\).
\[2(z-3)+1=\frac{10}{2}\]

5
Simplify  \(\frac{10}{2}\)  to  \(5\).
\[2(z-3)+1=5\]

6
Subtract \(1\) from both sides.
\[2(z-3)=5-1\]

7
Simplify  \(5-1\)  to  \(4\).
\[2(z-3)=4\]

8
Divide both sides by \(2\).
\[z-3=\frac{4}{2}\]

9
Simplify  \(\frac{4}{2}\)  to  \(2\).
\[z-3=2\]

10
Add \(3\) to both sides.
\[z=2+3\]

11
Simplify  \(2+3\)  to  \(5\).
\[z=5\]

Done
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