Problem of the Week

Updated at Jan 21, 2019 3:48 PM

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Jan 21, 2019

This week we have another algebra problem:

How can we factor \(10{x}^{2}-19x-15\)?

Let's start!

\[10{x}^{2}-19x-15\]

Split the second term in \(10{x}^{2}-19x-15\) into two terms

How?

\[10{x}^{2}+6x-25x-15\]

Factor out common terms in the first two terms, then in the last two terms

\[2x(5x+3)-5(5x+3)\]

Factor out the common term \(5x+3\)

\[(5x+3)(2x-5)\]

Done