Problem of the Week

Updated at Aug 3, 2020 5:16 PM

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Aug 3, 2020

For this week we've brought you this equation problem.

How would you solve the equation \(3-4\times \frac{5}{4q}=\frac{4}{3}\)?

Here are the steps:

\[3-4\times \frac{5}{4q}=\frac{4}{3}\]

Cancel \(4\).

\[3-\frac{5}{q}=\frac{4}{3}\]

Subtract \(3\) from both sides.

\[-\frac{5}{q}=\frac{4}{3}-3\]

Simplify \(\frac{4}{3}-3\) to \(-\frac{5}{3}\).

\[-\frac{5}{q}=-\frac{5}{3}\]

Multiply both sides by \(q\).

\[-5=-\frac{5}{3}q\]

Simplify \(\frac{5}{3}q\) to \(\frac{5q}{3}\).

\[-5=-\frac{5q}{3}\]

Multiply both sides by \(3\).

\[-5\times 3=-5q\]

Simplify \(-5\times 3\) to \(-15\).

\[-15=-5q\]

Divide both sides by \(-5\).

\[\frac{-15}{-5}=q\]

Two negatives make a positive.

\[\frac{15}{5}=q\]

Simplify \(\frac{15}{5}\) to \(3\).

\[3=q\]

Switch sides.

\[q=3\]

Done