Problem of the Week

Updated at Jul 15, 2019 11:45 AM

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Jul 15, 2019

This week's problem comes from the algebra category.

How can we factor \(15{x}^{2}-14x+3\)?

Let's begin!

\[15{x}^{2}-14x+3\]

How?

Split the second term in \(15{x}^{2}-14x+3\) into two terms.

\[15{x}^{2}-5x-9x+3\]

Factor out common terms in the first two terms, then in the last two terms.

\[5x(3x-1)-3(3x-1)\]

Factor out the common term \(3x-1\).

\[(3x-1)(5x-3)\]

Done