Problem of the Week

Updated at Jul 22, 2024 1:12 PM

How can we find the derivative of \({x}^{3}+\sqrt{x}\)?

Below is the solution.



\[\frac{d}{dx} {x}^{3}+\sqrt{x}\]

1
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[3{x}^{2}+\frac{{x}^{-\frac{1}{2}}}{2}\]

Done