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\[\frac{15{x}^{2}y-10x{y}^{2}}{\frac{5}{2}xy}\]
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(15x^(2)y-10xy^(2))/((5)/(2)xy)
(15x^(2)y-10xy^(2))/((5)/(2)xy)
\frac{{15x}^{(2)y}-{10xy}^{2}}{\frac{5}{(2)xy}}
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