Problem of the Week

Updated at May 5, 2014 5:51 PM

For this week we've brought you this calculus problem.

How can we find the derivative of $$\frac{1}{\sin^{2}x}$$?

Here are the steps:

$\frac{d}{dx} \frac{1}{\sin^{2}x}$

 1 Use Chain Rule on $$\frac{d}{dx} \frac{1}{\sin^{2}x}$$. Let $$u=\sin{x}$$. Use Power Rule: $$\frac{d}{du} {u}^{n}=n{u}^{n-1}$$.$-\frac{2}{\sin^{3}x}(\frac{d}{dx} \sin{x})$2 Use Trigonometric Differentiation: the derivative of $$\sin{x}$$ is $$\cos{x}$$.$-\frac{2\cos{x}}{\sin^{3}x}$Done-(2*cos(x))/sin(x)^3