Problem of the Week

Updated at Aug 17, 2015 5:04 PM

To get more practice in calculus, we brought you this problem of the week:

How would you differentiate \(\sec{x}+\sin{x}\)?

Check out the solution below!



\[\frac{d}{dx} \sec{x}+\sin{x}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dx} \sec{x})+(\frac{d}{dx} \sin{x})\]

2
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\sec{x}\tan{x}+(\frac{d}{dx} \sin{x})\]

3
Use Trigonometric Differentiation: the derivative of \(\sin{x}\) is \(\cos{x}\).
\[\sec{x}\tan{x}+\cos{x}\]

Done
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