Problem of the Week

Updated at Oct 9, 2017 8:23 AM

This week we have another algebra problem:

How can we compute the factors of \(15{x}^{2}-8x+1\)?

Let's start!



\[15{x}^{2}-8x+1\]

1
Split the second term in \(15{x}^{2}-8x+1\) into two terms.
\[15{x}^{2}-3x-5x+1\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[3x(5x-1)-(5x-1)\]

3
Factor out the common term \(5x-1\).
\[(5x-1)(3x-1)\]

Done