Problem of the Week

Updated at Feb 19, 2018 8:58 AM

This week we have another calculus problem:

How would you differentiate $$\sec{x}{e}^{x}$$?

Let's start!

$\frac{d}{dx} \sec{x}{e}^{x}$

 1 Use Product Rule to find the derivative of $$\sec{x}{e}^{x}$$. The product rule states that $$(fg)'=f'g+fg'$$.$(\frac{d}{dx} \sec{x}){e}^{x}+\sec{x}(\frac{d}{dx} {e}^{x})$2 Use Trigonometric Differentiation: the derivative of $$\sec{x}$$ is $$\sec{x}\tan{x}$$.$\sec{x}\tan{x}{e}^{x}+\sec{x}(\frac{d}{dx} {e}^{x})$3 The derivative of $${e}^{x}$$ is $${e}^{x}$$.$\sec{x}\tan{x}{e}^{x}+\sec{x}{e}^{x}$Donesec(x)*tan(x)*e^x+sec(x)*e^x