Problem of the Week

Updated at May 28, 2018 10:29 AM

To get more practice in algebra, we brought you this problem of the week:

How can we compute the factors of \(2{x}^{2}-10x-28\)?

Check out the solution below!



\[2{x}^{2}-10x-28\]

1
Find the Greatest Common Factor (GCF).
GCF = \(2\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[2(\frac{2{x}^{2}}{2}+\frac{-10x}{2}-\frac{28}{2})\]

3
Simplify each term in parentheses.
\[2({x}^{2}-5x-14)\]

4
Factor \({x}^{2}-5x-14\).
\[2(x-7)(x+2)\]

Done
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