Problem of the Week

Updated at Aug 27, 2018 12:06 PM

For this week we've brought you this algebra problem.

How can we factor \(7{n}^{2}-31n-20\)?

Here are the steps:



\[7{n}^{2}-31n-20\]

1
Split the second term in \(7{n}^{2}-31n-20\) into two terms.
\[7{n}^{2}+4n-35n-20\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[n(7n+4)-5(7n+4)\]

3
Factor out the common term \(7n+4\).
\[(7n+4)(n-5)\]

Done
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