Problem of the Week

Updated at Oct 15, 2018 3:04 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation \({(y-3)}^{2}\times \frac{5}{4y}=0\)?

Check out the solution below!



\[{(y-3)}^{2}\times \frac{5}{4y}=0\]

1
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{{(y-3)}^{2}\times 5}{4y}=0\]

2
Regroup terms.
\[\frac{5{(y-3)}^{2}}{4y}=0\]

3
Multiply both sides by \(4y\).
\[5{(y-3)}^{2}=0\]

4
Divide both sides by \(5\).
\[{(y-3)}^{2}=0\]

5
Take the square root of both sides.
\[y-3=0\]

6
Add \(3\) to both sides.
\[y=3\]

Done
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