# Problem of the Week

## Updated at Oct 15, 2018 3:04 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation $${(y-3)}^{2}\times \frac{5}{4y}=0$$?

Check out the solution below!

${(y-3)}^{2}\times \frac{5}{4y}=0$

 1 Use this rule: $$a \times \frac{b}{c}=\frac{ab}{c}$$.$\frac{{(y-3)}^{2}\times 5}{4y}=0$2 Regroup terms.$\frac{5{(y-3)}^{2}}{4y}=0$3 Multiply both sides by $$4y$$.$5{(y-3)}^{2}=0$4 Divide both sides by $$5$$.${(y-3)}^{2}=0$5 Take the square root of both sides.$y-3=0$6 Add $$3$$ to both sides.$y=3$Doney=3