Problem of the Week

Updated at Dec 31, 2018 4:43 PM

This week we have another equation problem:

How would you solve the equation \(\frac{4t-3}{5}+2=\frac{23}{5}\)?

Let's start!



\[\frac{4t-3}{5}+2=\frac{23}{5}\]

1
Subtract \(2\) from both sides
\[\frac{4t-3}{5}=\frac{23}{5}-2\]

2
Simplify \(\frac{23}{5}-2\) to \(\frac{13}{5}\)
\[\frac{4t-3}{5}=\frac{13}{5}\]

3
Multiply both sides by \(5\)
\[4t-3=\frac{13}{5}\times 5\]

4
Simplify \(\frac{13}{5}\times 5\) to \(\frac{65}{5}\)
\[4t-3=\frac{65}{5}\]

5
Simplify \(\frac{65}{5}\) to \(13\)
\[4t-3=13\]

6
Add \(3\) to both sides
\[4t=13+3\]

7
Simplify \(13+3\) to \(16\)
\[4t=16\]

8
Divide both sides by \(4\)
\[t=\frac{16}{4}\]

9
Simplify \(\frac{16}{4}\) to \(4\)
\[t=4\]

Done