# Problem of the Week

## Updated at Dec 31, 2018 4:43 PM

This week we have another equation problem:

How would you solve the equation $$\frac{4t-3}{5}+2=\frac{23}{5}$$?

Let's start!

$\frac{4t-3}{5}+2=\frac{23}{5}$

 1 Subtract $$2$$ from both sides.$\frac{4t-3}{5}=\frac{23}{5}-2$2 Simplify  $$\frac{23}{5}-2$$  to  $$\frac{13}{5}$$.$\frac{4t-3}{5}=\frac{13}{5}$3 Multiply both sides by $$5$$.$4t-3=\frac{13}{5}\times 5$4 Cancel $$5$$.$4t-3=13$5 Add $$3$$ to both sides.$4t=13+3$6 Simplify  $$13+3$$  to  $$16$$.$4t=16$7 Divide both sides by $$4$$.$t=\frac{16}{4}$8 Simplify  $$\frac{16}{4}$$  to  $$4$$.$t=4$Donet=4