# Problem of the Week

Updated at Dec 31, 2018 4:43 PM

This week we have another equation problem:

How would you solve the equation $$\frac{4t-3}{5}+2=\frac{23}{5}$$?

Let's start!

$\frac{4t-3}{5}+2=\frac{23}{5}$

 1 Subtract $$2$$ from both sides$\frac{4t-3}{5}=\frac{23}{5}-2$2 Simplify $$\frac{23}{5}-2$$ to $$\frac{13}{5}$$$\frac{4t-3}{5}=\frac{13}{5}$3 Multiply both sides by $$5$$$4t-3=\frac{13}{5}\times 5$4 Simplify $$\frac{13}{5}\times 5$$ to $$\frac{65}{5}$$$4t-3=\frac{65}{5}$5 Simplify $$\frac{65}{5}$$ to $$13$$$4t-3=13$6 Add $$3$$ to both sides$4t=13+3$7 Simplify $$13+3$$ to $$16$$$4t=16$8 Divide both sides by $$4$$$t=\frac{16}{4}$9 Simplify $$\frac{16}{4}$$ to $$4$$$t=4$Donet=4