Problem of the Week

Updated at Jan 14, 2019 5:21 PM

For this week we've brought you this algebra problem.

How can we factor \({n}^{2}-10n+21\)?

Here are the steps:



\[{n}^{2}-10n+21\]

1
Ask: Which two numbers add up to \(-10\) and multiply to \(21\)?
\(-7\) and \(-3\)

2
Rewrite the expression using the above
\[(n-7)(n-3)\]

Done