# Problem of the Week

## Updated at Jan 14, 2019 5:21 PM

For this week we've brought you this algebra problem.

How can we factor $${n}^{2}-10n+21$$?

Here are the steps:

${n}^{2}-10n+21$

 1 Ask: Which two numbers add up to $$-10$$ and multiply to $$21$$?$$-7$$ and $$-3$$2 Rewrite the expression using the above.$(n-7)(n-3)$Done(n-7)*(n-3)