Problem of the Week

Updated at Feb 18, 2019 4:06 PM

For this week we've brought you this calculus problem.

How can we find the derivative of \(\ln{z}+{z}^{3}\)?

Here are the steps:



\[\frac{d}{dz} \ln{z}+{z}^{3}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dz} \ln{z})+(\frac{d}{dz} {z}^{3})\]

2
The derivative of \(\ln{x}\) is \(\frac{1}{x}\).
\[\frac{1}{z}+(\frac{d}{dz} {z}^{3})\]

3
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[\frac{1}{z}+3{z}^{2}\]

Done