# Problem of the Week

## Updated at Oct 14, 2019 4:41 PM

For this week we've brought you this calculus problem.

How can we solve for the derivative of $${t}^{7}+{e}^{t}$$?

Here are the steps:

$\frac{d}{dt} {t}^{7}+{e}^{t}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dt} {t}^{7})+(\frac{d}{dt} {e}^{t})$2 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$7{t}^{6}+(\frac{d}{dt} {e}^{t})$3 The derivative of $${e}^{x}$$ is $${e}^{x}$$.$7{t}^{6}+{e}^{t}$Done7*t^6+e^t