Problem of the Week

Updated at May 4, 2020 4:14 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve \(\frac{2(3-z)}{3-{z}^{2}}=2\)?

Check out the solution below!



\[\frac{2(3-z)}{3-{z}^{2}}=2\]

1
Multiply both sides by \(3-{z}^{2}\).
\[2(3-z)=2(3-{z}^{2})\]

2
Cancel \(2\) on both sides.
\[3-z=3-{z}^{2}\]

3
Cancel \(3\) on both sides.
\[-z=-{z}^{2}\]

4
Move all terms to one side.
\[z-{z}^{2}=0\]

5
Factor out the common term \(z\).
\[z(1-z)=0\]

6
Solve for \(z\).
\[z=0,1\]

Done