Problem of the Week

Updated at Aug 3, 2020 5:16 PM

For this week we've brought you this equation problem.

How would you solve the equation \(3-4\times \frac{5}{4q}=\frac{4}{3}\)?

Here are the steps:



\[3-4\times \frac{5}{4q}=\frac{4}{3}\]

1
Cancel \(4\).
\[3-\frac{5}{q}=\frac{4}{3}\]

2
Subtract \(3\) from both sides.
\[-\frac{5}{q}=\frac{4}{3}-3\]

3
Simplify  \(\frac{4}{3}-3\)  to  \(-\frac{5}{3}\).
\[-\frac{5}{q}=-\frac{5}{3}\]

4
Multiply both sides by \(q\).
\[-5=-\frac{5}{3}q\]

5
Simplify  \(\frac{5}{3}q\)  to  \(\frac{5q}{3}\).
\[-5=-\frac{5q}{3}\]

6
Multiply both sides by \(3\).
\[-5\times 3=-5q\]

7
Simplify  \(-5\times 3\)  to  \(-15\).
\[-15=-5q\]

8
Divide both sides by \(-5\).
\[\frac{-15}{-5}=q\]

9
Two negatives make a positive.
\[\frac{15}{5}=q\]

10
Simplify  \(\frac{15}{5}\)  to  \(3\).
\[3=q\]

11
Switch sides.
\[q=3\]

Done
Cymath foriOSAndroid