Problem of the Week

Updated at Apr 5, 2021 2:35 PM

This week's problem comes from the equation category.

How would you solve \(4(2+2(3-t))=8\)?

Let's begin!



\[4(2+2(3-t))=8\]

1
Divide both sides by \(4\).
\[2+2(3-t)=\frac{8}{4}\]

2
Simplify  \(\frac{8}{4}\)  to  \(2\).
\[2+2(3-t)=2\]

3
Cancel \(2\) on both sides.
\[2(3-t)=0\]

4
Divide both sides by \(2\).
\[3-t=0\]

5
Subtract \(3\) from both sides.
\[-t=-3\]

6
Multiply both sides by \(-1\).
\[t=3\]

Done
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