Problem of the Week

Updated at Apr 19, 2021 4:23 PM

This week we have another calculus problem:

How can we solve for the derivative of \(13t+\sqrt{t}\)?

Let's start!



\[\frac{d}{dt} 13t+\sqrt{t}\]

1
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[13+\frac{1}{2\sqrt{t}}\]

Done
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