# Problem of the Week

## Updated at Apr 19, 2021 4:23 PM

This week we have another calculus problem:

How can we solve for the derivative of $$13t+\sqrt{t}$$?

Let's start!

$\frac{d}{dt} 13t+\sqrt{t}$

 1 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$13+\frac{1}{2\sqrt{t}}$Done13+1/(2*sqrt(t))