Problem of the Week

Updated at Oct 4, 2021 5:16 PM

For this week we've brought you this algebra problem.

How would you find the factors of \(4{w}^{2}-4w-8\)?

Here are the steps:



\[4{w}^{2}-4w-8\]

1
Find the Greatest Common Factor (GCF).
GCF = \(4\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[4(\frac{4{w}^{2}}{4}+\frac{-4w}{4}-\frac{8}{4})\]

3
Simplify each term in parentheses.
\[4({w}^{2}-w-2)\]

4
Factor \({w}^{2}-w-2\).
\[4(w-2)(w+1)\]

Done
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