Problem of the Week

Updated at Jun 30, 2025 11:29 AM

To get more practice in calculus, we brought you this problem of the week:

How can we solve for the derivative of \(13p+\sec{p}\)?

Check out the solution below!



\[\frac{d}{dp} 13p+\sec{p}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dp} 13p)+(\frac{d}{dp} \sec{p})\]

2
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[13+(\frac{d}{dp} \sec{p})\]

3
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[13+\sec{p}\tan{p}\]

Done
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