Problem of the Week

Updated at Apr 27, 2026 12:07 PM

How would you find the factors of \(10{y}^{2}-21y-10\)?

Below is the solution.



\[10{y}^{2}-21y-10\]

1
Split the second term in \(10{y}^{2}-21y-10\) into two terms.
\[10{y}^{2}+4y-25y-10\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[2y(5y+2)-5(5y+2)\]

3
Factor out the common term \(5y+2\).
\[(5y+2)(2y-5)\]

Done
Cymath foriOSAndroid