# Problem of the Week

## Updated at Aug 11, 2014 2:48 PM

This week we have another calculus problem:

How can we find the derivative of $$\sin{x}+\ln{x}$$?

Let's start!

$\frac{d}{dx} \sin{x}+\ln{x}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} \sin{x})+(\frac{d}{dx} \ln{x})$2 Use Trigonometric Differentiation: the derivative of $$\sin{x}$$ is $$\cos{x}$$.$\cos{x}+(\frac{d}{dx} \ln{x})$3 The derivative of $$\ln{x}$$ is $$\frac{1}{x}$$.$\cos{x}+\frac{1}{x}$Donecos(x)+1/x