# Problem of the Week

## Updated at Apr 13, 2015 9:00 AM

This week's problem comes from the calculus category.

How can we find the derivative of $$x+\sec{x}$$?

Let's begin!

$\frac{d}{dx} x+\sec{x}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} x)+(\frac{d}{dx} \sec{x})$2 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$1+(\frac{d}{dx} \sec{x})$3 Use Trigonometric Differentiation: the derivative of $$\sec{x}$$ is $$\sec{x}\tan{x}$$.$1+\sec{x}\tan{x}$Done1+sec(x)*tan(x)