Problem of the Week

Updated at Jul 17, 2017 8:05 AM

This week's problem comes from the algebra category.

How can we compute the factors of \(42{x}^{2}+43x-7\)?

Let's begin!



\[42{x}^{2}+43x-7\]

1
Split the second term in \(42{x}^{2}+43x-7\) into two terms.
\[42{x}^{2}+49x-6x-7\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[7x(6x+7)-(6x+7)\]

3
Factor out the common term \(6x+7\).
\[(6x+7)(7x-1)\]

Done