Problem of the Week

Updated at Jul 9, 2018 3:02 PM

How can we solve for the derivative of \(\tan{x}+{x}^{8}\)?

Below is the solution.



\[\frac{d}{dx} \tan{x}+{x}^{8}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dx} \tan{x})+(\frac{d}{dx} {x}^{8})\]

2
Use Trigonometric Differentiation: the derivative of \(\tan{x}\) is \(\sec^{2}x\).
\[\sec^{2}x+(\frac{d}{dx} {x}^{8})\]

3
Use Power Rule: \(\frac{d}{dx} {x}^{n}=n{x}^{n-1}\).
\[\sec^{2}x+8{x}^{7}\]

Done