# Problem of the Week

Updated at Nov 12, 2018 1:10 PM

This week's problem comes from the calculus category.

How would you differentiate $$\tan{x}+{x}^{9}$$?

Let's begin!

$\frac{d}{dx} \tan{x}+{x}^{9}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$$(\frac{d}{dx} \tan{x})+(\frac{d}{dx} {x}^{9})$2 The derivative of $$\tan{x}$$ is $$\sec^{2}x$$$\sec^{2}x+(\frac{d}{dx} {x}^{9})$3 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$$\sec^{2}x+9{x}^{8}$Donesec(x)^2+9*x^8