Problem of the Week

Updated at Jun 17, 2019 9:47 AM

How can we compute the factors of \(2{m}^{2}-8m-24\)?

Below is the solution.



\[2{m}^{2}-8m-24\]

1
Find the Greatest Common Factor (GCF).
GCF = \(2\)

2
Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
\[2(\frac{2{m}^{2}}{2}+\frac{-8m}{2}-\frac{24}{2})\]

3
Simplify each term in parentheses.
\[2({m}^{2}-4m-12)\]

4
Factor \({m}^{2}-4m-12\).
\[2(m-6)(m+2)\]

Done
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