Problem of the Week

Updated at Oct 7, 2019 12:39 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of \(\ln{m}+\sec{m}\)?

Check out the solution below!



\[\frac{d}{dm} \ln{m}+\sec{m}\]

1
Use Sum Rule: \(\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))\).
\[(\frac{d}{dm} \ln{m})+(\frac{d}{dm} \sec{m})\]

2
The derivative of \(\ln{x}\) is \(\frac{1}{x}\).
\[\frac{1}{m}+(\frac{d}{dm} \sec{m})\]

3
Use Trigonometric Differentiation: the derivative of \(\sec{x}\) is \(\sec{x}\tan{x}\).
\[\frac{1}{m}+\sec{m}\tan{m}\]

Done
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