# Problem of the Week

## Updated at Dec 2, 2019 2:53 PM

This week we have another equation problem:

How would you solve $$\frac{4(z-3)+2}{5}=2$$?

Let's start!

$\frac{4(z-3)+2}{5}=2$

 1 Factor out the common term $$2$$.$\frac{2(2(z-3)+1)}{5}=2$2 Multiply both sides by $$5$$.$2(2(z-3)+1)=2\times 5$3 Simplify  $$2\times 5$$  to  $$10$$.$2(2(z-3)+1)=10$4 Divide both sides by $$2$$.$2(z-3)+1=\frac{10}{2}$5 Simplify  $$\frac{10}{2}$$  to  $$5$$.$2(z-3)+1=5$6 Subtract $$1$$ from both sides.$2(z-3)=5-1$7 Simplify  $$5-1$$  to  $$4$$.$2(z-3)=4$8 Divide both sides by $$2$$.$z-3=\frac{4}{2}$9 Simplify  $$\frac{4}{2}$$  to  $$2$$.$z-3=2$10 Add $$3$$ to both sides.$z=2+3$11 Simplify  $$2+3$$  to  $$5$$.$z=5$Donez=5