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English
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Problem of the Week
Updated at Dec 16, 2019 5:03 PMThis week we have another equation problem: How can we solve the equation \(\frac{25({y}^{2}-3)}{y}=-50\)? Let's start! \[\frac{25({y}^{2}-3)}{y}=-50\]
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This week we have another equation problem: How can we solve the equation \(\frac{25({y}^{2}-3)}{y}=-50\)? Let's start! \[\frac{25({y}^{2}-3)}{y}=-50\]
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