# Problem of the Week

## Updated at Jan 6, 2020 11:49 AM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation $$\frac{{m}^{2}+2}{2}-3=6$$?

Check out the solution below!

$\frac{{m}^{2}+2}{2}-3=6$

 1 Simplify  $$\frac{{m}^{2}+2}{2}$$  to  $$1+\frac{{m}^{2}}{2}$$.$1+\frac{{m}^{2}}{2}-3=6$2 Simplify  $$1+\frac{{m}^{2}}{2}-3$$  to  $$\frac{{m}^{2}}{2}-2$$.$\frac{{m}^{2}}{2}-2=6$3 Add $$2$$ to both sides.$\frac{{m}^{2}}{2}=6+2$4 Simplify  $$6+2$$  to  $$8$$.$\frac{{m}^{2}}{2}=8$5 Multiply both sides by $$2$$.${m}^{2}=8\times 2$6 Simplify  $$8\times 2$$  to  $$16$$.${m}^{2}=16$7 Take the square root of both sides.$m=\pm \sqrt{16}$8 Since $$4\times 4=16$$, the square root of $$16$$ is $$4$$.$m=\pm 4$Donem=4,-4