Problem of the Week

Updated at Apr 20, 2020 1:46 PM

For this week we've brought you this equation problem.

How would you solve the equation $$\frac{10(3-n)}{2+n}=\frac{20}{3}$$?

Here are the steps:

$\frac{10(3-n)}{2+n}=\frac{20}{3}$

 1 Multiply both sides by $$2+n$$.$10(3-n)=\frac{20}{3}(2+n)$2 Simplify  $$\frac{20}{3}(2+n)$$  to  $$\frac{20(2+n)}{3}$$.$10(3-n)=\frac{20(2+n)}{3}$3 Multiply both sides by $$3$$.$30(3-n)=20(2+n)$4 Expand.$90-30n=40+20n$5 Add $$30n$$ to both sides.$90=40+20n+30n$6 Simplify  $$40+20n+30n$$  to  $$40+50n$$.$90=40+50n$7 Subtract $$40$$ from both sides.$90-40=50n$8 Simplify  $$90-40$$  to  $$50$$.$50=50n$9 Divide both sides by $$50$$.$1=n$10 Switch sides.$n=1$Donen=1