# Problem of the Week

## Updated at Sep 11, 2023 11:59 AM

To get more practice in algebra, we brought you this problem of the week:

How can we compute the factors of $$28{x}^{2}-63x+35$$?

Check out the solution below!

$28{x}^{2}-63x+35$

 1 Find the Greatest Common Factor (GCF).1 What is the largest number that divides evenly into $$28{x}^{2}$$, $$-63x$$, and $$35$$?It is $$7$$.2 What is the highest degree of $$x$$ that divides evenly into $$28{x}^{2}$$, $$-63x$$, and $$35$$?It is 1, since $$x$$ is not in every term.3 Multiplying the results above,The GCF is $$7$$.To get access to all 'How?' and 'Why?' steps, join Cymath Plus!GCF = $$7$$2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)$7(\frac{28{x}^{2}}{7}+\frac{-63x}{7}+\frac{35}{7})$3 Simplify each term in parentheses.$7(4{x}^{2}-9x+5)$4 Split the second term in $$4{x}^{2}-9x+5$$ into two terms.1 Multiply the coefficient of the first term by the constant term.$4\times 5=20$2 Ask: Which two numbers add up to $$-9$$ and multiply to $$20$$?$$-4$$ and $$-5$$3 Split $$-9x$$ as the sum of $$-4x$$ and $$-5x$$.$4{x}^{2}-4x-5x+5$To get access to all 'How?' and 'Why?' steps, join Cymath Plus!$7(4{x}^{2}-4x-5x+5)$5 Factor out common terms in the first two terms, then in the last two terms.$7(4x(x-1)-5(x-1))$6 Factor out the common term $$x-1$$.$7(x-1)(4x-5)$Done 7*(x-1)*(4*x-5)