Problem of the Week

Updated at Feb 12, 2024 4:37 PM

How would you find the factors of \(3{v}^{2}-16v+16\)?

Below is the solution.



\[3{v}^{2}-16v+16\]

1
Split the second term in \(3{v}^{2}-16v+16\) into two terms.
\[3{v}^{2}-4v-12v+16\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[v(3v-4)-4(3v-4)\]

3
Factor out the common term \(3v-4\).
\[(3v-4)(v-4)\]

Done
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