Problem of the Week

Updated at Jun 15, 2026 12:36 PM

For this week we've brought you this algebra problem.

How can we factor \(3{v}^{2}-28v+49\)?

Here are the steps:



\[3{v}^{2}-28v+49\]

1
Split the second term in \(3{v}^{2}-28v+49\) into two terms.
\[3{v}^{2}-7v-21v+49\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[v(3v-7)-7(3v-7)\]

3
Factor out the common term \(3v-7\).
\[(3v-7)(v-7)\]

Done
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