# Problem of the Week

## Updated at Sep 29, 2014 8:32 AM

How can we solve for the derivative of $${x}^{2}+{e}^{x}$$?

Below is the solution.

$\frac{d}{dx} {x}^{2}+{e}^{x}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} {x}^{2})+(\frac{d}{dx} {e}^{x})$2 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$2x+(\frac{d}{dx} {e}^{x})$3 The derivative of $${e}^{x}$$ is $${e}^{x}$$.$2x+{e}^{x}$Done2*x+e^x