# Problem of the Week

## Updated at Jun 15, 2015 5:33 PM

This week we have another calculus problem:

How can we find the derivative of $$\csc{x}-3x$$?

Let's start!

$\frac{d}{dx} \csc{x}-3x$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} \csc{x})+(\frac{d}{dx} -3x)$2 Use Trigonometric Differentiation: the derivative of $$\csc{x}$$ is $$-\csc{x}\cot{x}$$.$-\csc{x}\cot{x}+(\frac{d}{dx} -3x)$3 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$-\csc{x}\cot{x}-3$Done-csc(x)*cot(x)-3