Problem of the Week

Updated at Feb 9, 2026 8:04 AM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation \((3-4y)\times \frac{5}{y-3}=25\)?

Check out the solution below!



\[(3-4y)\times \frac{5}{y-3}=25\]

1
Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[\frac{(3-4y)\times 5}{y-3}=25\]

2
Regroup terms.
\[\frac{5(3-4y)}{y-3}=25\]

3
Multiply both sides by \(y-3\).
\[5(3-4y)=25(y-3)\]

4
Divide both sides by \(5\).
\[3-4y=5(y-3)\]

5
Expand.
\[3-4y=5y-15\]

6
Add \(4y\) to both sides.
\[3=5y-15+4y\]

7
Simplify  \(5y-15+4y\)  to  \(9y-15\).
\[3=9y-15\]

8
Add \(15\) to both sides.
\[3+15=9y\]

9
Simplify  \(3+15\)  to  \(18\).
\[18=9y\]

10
Divide both sides by \(9\).
\[\frac{18}{9}=y\]

11
Simplify  \(\frac{18}{9}\)  to  \(2\).
\[2=y\]

12
Switch sides.
\[y=2\]

Done
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