# Problem of the Week

## Updated at Sep 14, 2015 2:16 PM

For this week we've brought you this calculus problem.

How would you differentiate $$\sec{x}+\sin{x}$$?

Here are the steps:

$\frac{d}{dx} \sec{x}+\sin{x}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{dx} \sec{x})+(\frac{d}{dx} \sin{x})$2 Use Trigonometric Differentiation: the derivative of $$\sec{x}$$ is $$\sec{x}\tan{x}$$.$\sec{x}\tan{x}+(\frac{d}{dx} \sin{x})$3 Use Trigonometric Differentiation: the derivative of $$\sin{x}$$ is $$\cos{x}$$.$\sec{x}\tan{x}+\cos{x}$Donesec(x)*tan(x)+cos(x)