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How would you solve \(\frac{\frac{t-3}{3}+2}{3}=\frac{8}{9}\)? Below is the solution. \[\frac{\frac{t-3}{3}+2}{3}=\frac{8}{9}\]
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How would you solve \(\frac{\frac{t-3}{3}+2}{3}=\frac{8}{9}\)? Below is the solution. \[\frac{\frac{t-3}{3}+2}{3}=\frac{8}{9}\]
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