Problem of the Week

Updated at May 20, 2019 3:51 PM

For this week we've brought you this algebra problem.

How can we factor \(14{m}^{2}-31m+15\)?

Here are the steps:



\[14{m}^{2}-31m+15\]

1
Split the second term in \(14{m}^{2}-31m+15\) into two terms.
\[14{m}^{2}-10m-21m+15\]

2
Factor out common terms in the first two terms, then in the last two terms.
\[2m(7m-5)-3(7m-5)\]

3
Factor out the common term \(7m-5\).
\[(7m-5)(2m-3)\]

Done
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