Problem of the Week

Updated at Sep 16, 2019 4:41 PM

For this week we've brought you this equation problem.

How would you solve \(\frac{u}{4\times 5}\times \frac{u-3}{5}=-\frac{1}{50}\)?

Here are the steps:



\[\frac{u}{4\times 5}\times \frac{u-3}{5}=-\frac{1}{50}\]

1
Simplify  \(4\times 5\)  to  \(20\).
\[\frac{u}{20}\times \frac{u-3}{5}=-\frac{1}{50}\]

2
Simplify  \(\frac{u}{20}\times \frac{u-3}{5}\)  to  \(\frac{u(u-3)}{100}\).
\[\frac{u(u-3)}{100}=-\frac{1}{50}\]

3
Multiply both sides by \(100\).
\[u(u-3)=-2\]

4
Expand.
\[{u}^{2}-3u=-2\]

5
Move all terms to one side.
\[{u}^{2}-3u+2=0\]

6
How?
Factor \({u}^{2}-3u+2\).
\[(u-2)(u-1)=0\]

7
How?
Solve for \(u\).
\[u=2,1\]

Done