Problem of the Week

Updated at Oct 28, 2019 12:04 PM

To get more practice in equation, we brought you this problem of the week:

How would you solve the equation \(3(x-3)(4x+4)=60\)?

Check out the solution below!



\[3(x-3)(4x+4)=60\]

1
Expand.
\[12{x}^{2}+12x-36x-36=60\]

2
Simplify  \(12{x}^{2}+12x-36x-36\)  to  \(12{x}^{2}-24x-36\).
\[12{x}^{2}-24x-36=60\]

3
Move all terms to one side.
\[12{x}^{2}-24x-36-60=0\]

4
Simplify  \(12{x}^{2}-24x-36-60\)  to  \(12{x}^{2}-24x-96\).
\[12{x}^{2}-24x-96=0\]

5
Factor out the common term \(12\).
\[12({x}^{2}-2x-8)=0\]

6
How?
Factor \({x}^{2}-2x-8\).
\[12(x-4)(x+2)=0\]

7
How?
Solve for \(x\).
\[x=4,-2\]

Done