Problem of the Week

Updated at Apr 27, 2020 2:54 PM

To get more practice in calculus, we brought you this problem of the week:

How can we find the derivative of $$6u+\sec{u}$$?

Check out the solution below!

$\frac{d}{du} 6u+\sec{u}$

 1 Use Sum Rule: $$\frac{d}{dx} f(x)+g(x)=(\frac{d}{dx} f(x))+(\frac{d}{dx} g(x))$$.$(\frac{d}{du} 6u)+(\frac{d}{du} \sec{u})$2 Use Power Rule: $$\frac{d}{dx} {x}^{n}=n{x}^{n-1}$$.$6+(\frac{d}{du} \sec{u})$3 Use Trigonometric Differentiation: the derivative of $$\sec{x}$$ is $$\sec{x}\tan{x}$$.$6+\sec{u}\tan{u}$Done6+sec(u)*tan(u)