# Problem of the Week

## Updated at May 11, 2020 1:03 PM

This week we have another equation problem:

How can we solve the equation $$\frac{\frac{t-3}{3}+2}{5}=\frac{7}{15}$$?

Let's start!

$\frac{\frac{t-3}{3}+2}{5}=\frac{7}{15}$

 1 Simplify  $$\frac{t-3}{3}$$  to  $$-1+\frac{t}{3}$$.$\frac{-1+\frac{t}{3}+2}{5}=\frac{7}{15}$2 Simplify  $$-1+\frac{t}{3}+2$$  to  $$\frac{t}{3}+1$$.$\frac{\frac{t}{3}+1}{5}=\frac{7}{15}$3 Simplify  $$\frac{\frac{t}{3}+1}{5}$$  to  $$\frac{\frac{t}{3}}{5}+\frac{1}{5}$$.$\frac{\frac{t}{3}}{5}+\frac{1}{5}=\frac{7}{15}$4 Simplify  $$\frac{\frac{t}{3}}{5}$$  to  $$\frac{t}{3\times 5}$$.$\frac{t}{3\times 5}+\frac{1}{5}=\frac{7}{15}$5 Simplify  $$3\times 5$$  to  $$15$$.$\frac{t}{15}+\frac{1}{5}=\frac{7}{15}$6 Subtract $$\frac{1}{5}$$ from both sides.$\frac{t}{15}=\frac{7}{15}-\frac{1}{5}$7 Simplify  $$\frac{7}{15}-\frac{1}{5}$$  to  $$\frac{4}{15}$$.$\frac{t}{15}=\frac{4}{15}$8 Multiply both sides by $$15$$.$t=\frac{4}{15}\times 15$9 Cancel $$15$$.$t=4$Done t=4